00:01
In this question, we have a loop, which is in the rectangular shape carrying a current of one ampth.
00:05
It has a width of 30 centimetres, so this is 30 centimetres, and a height of 0 .2 metres, so 20 centimetres.
00:17
We're told it carries one amp of current clockwise around the loop.
00:21
We want to first find the magnetic force on each side of the loop if there is a magnetic field of 2 .5 tesla's directed out of the page.
00:29
So first we'll calculate it on the top section of wire, so this section of wire here.
00:34
We know that the force is equal to the current times the length crossed with the magnetic field, so i -l -b in this case as their perpendicular.
00:46
We know the current is one amp.
00:49
We know the length is 0 .3 metres, because it's 30 centimetres, and we know the magnetic field is 2 .5 tesla's.
00:58
So calculating this, we get a force equal to 0 .75 newtons.
01:05
Using the right -hand rule, we can also calculate that the direction of this is in the negative y direction.
01:15
Applying the same principle for the bottom stretch of wire, so this stretch here, we can say that it is equal to again 1 times 0 .3 times 2 .5, which is again equal to 0 .75 newtons...