A 20.0 cm ×30.0 cm rectangular loop of wire carries 1.0 A of current clockwise around the -30

step 1 In this given problem there is a rectangular loop of fire which is kept in a magnetic field. Mag

A 20.0 cm ×30.0 cm rectangular loop of wire carries 1.0 A...

A $20.0 \mathrm{~cm} \times 30.0 \mathrm{~cm}$ rectangular loop of wire carries $1.0 \mathrm{~A}$ of current clockwise around the $-30$ loop. (a) Find the magnetic force on each side $\operatorname{Pr}$ of the loop if the magnetic field is $2.5 \mathrm{~T}$ out of the page. (b) What is the net magnetic force on the loop?

Labs

Want to see this concept in action?

NEW

Explore this concept interactively to see how it behaves as you change inputs.

View Labs

Key Concepts

Cross Product and Right-Hand Rule

The evaluation of the magnetic force on a conductor involves the vector cross product between the current's direction (represented by the length vector of the wire segment) and the magnetic field. The direction of the resulting force is determined using the right-hand rule, which is essential for identifying the orientation of forces in magnetic environments.

Net Force on a Closed Current Loop in a Uniform Magnetic Field

In a uniform magnetic field, while individual segments of a closed current loop experience magnetic forces, the overall net force on the loop is typically zero due to symmetry and the cancellation of forces. This principle is crucial in understanding that although there may be torques acting on the loop, the sum of the forces can cancel out, resulting in no translational motion.

Magnetic Force on a Current-Carrying Conductor

This concept involves understanding that a current-carrying conductor placed in a magnetic field will experience a force given by the equation F = I(L × B), where I is the current, L is the length vector of the conductor, and B is the magnetic field. This is a fundamental aspect of electromagnetism and is derived from the Lorentz force law, which applies to moving charges in a magnetic field.

Transcript

Please give Ace some feedback