Question
A 950 -kg cylindrical can buoy floats vertically in salt water. The diameter of the buoy is 0.900 $\mathrm{m}$ . (a) Calculate the additional distance the buoy will sink when a $70.0-\mathrm{kg}$ man stands on top. (Use the expression derived in part (b) of Problem $14.66 .$ ) (b) Calculate the period of the resulting vertical SHM when the man dives off. (Use the expression derived in part (c) of Problem 14.66 , and as in that problem, you can ignore the damping due to fluid friction.)
Step 1
Given that the diameter of the buoy is 0.900 m, the radius is half of this, or 0.450 m. So, the cross-sectional area is $A = \pi (0.450 \, \text{m})^2 = 0.636 \, \text{m}^2$. Show more…
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CP A 950 -kg, cylindrical can buoy floats vertically in salt water. The diameter of the buoy is 0.900 $\mathrm{m}$ . (a) Calculate the additional distance the buoy will sink when a 70.0 -kg man stands on top of it. (Use the expression derived in part (b) of Problem 14.76.) (b) Calculate the period of the resulting vertical SHM when the man dives off. (Use the expression derived in part (c) of Problem 14.76 , and as in that problem, you can ignore the damping due to fluid friction.)
A 950-kg cylindrical can buoy floats vertically in saltwater. The diameter of the buoy is 0.900 m. Calculate the additional distance the buoy will sink when a 70.0-kg man stands on top of it.
A 950-kg cylindrical can buoy floats vertically in seawater. The diameter of the buoy is 0.900 m. Calculate the additional distance the buoy will sink when an 80.0-kg man stands on top of it.
Fluid Mechanics
Buoyancy
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