00:01
In question a, we have to find what is the debrilis wavelength of a bullet that has a mass of 10 grams and a speed of 300 meters per second.
00:09
We have to remember that according to the debril e formula, the momentum p of a particle is equal to the plunks constant divided by lambda.
00:19
So lambda is equal to h divided by the momentum, and the momentum can be written as m times v.
00:26
So in our case, we have that h is 6 .63 times 10 to the minus 34 jule second.
00:35
The mass is 0 .01 kilograms, so that's 10 grams, times 300 meters per second.
00:45
So this is 6 .63 divided by 3 times 10 to the minus 34 kilograms meters per second.
00:55
And we have that lambda is equal to 2 .21 times 10 to minus 34 kilograms meters per second.
01:10
This is the wavelength of the bullet.
01:14
In question b, we have to compare this wavelength with the diameter of a proton, which is approximately one phantometer or 10 to minus 15 meters...