00:01
We have a copper wire which has a cross -sectional area of 2 .5 millimeters squared.
00:06
Divide by 1 ,000 twice because of that square to get to meter squared.
00:14
And we're told that there is a current of 13 .5 millie -amps passing through this wire, divide by 1 ,000 to get amps.
00:26
We want to know what the potential difference would be if this wire were 2 meters long.
00:30
We know the resistivity of copper, which is a known amount, is 1 .72 times 10 to the negative 8 omic meters.
00:39
So the first thing we're going to do is find resistance from the equation of resistance equals to resistivity times length divided by cross -sectional area.
00:47
So we have 1 .72 times 10 to the negative 8 times 2 divided by 2 .5 times 10 to the negative 6.
00:59
And so our resistance for this would be 0 .0138 oms.
01:07
Now we can use the equation.
01:10
Potential difference is equal to current times resistance.
01:14
And so we have 13 .5 times 10 to the negative 3 times our 0 .0138.
01:23
And when we do this, we get a potential difference of 1 .86 times 10 to the negative 4 bolts...