00:01
Man, all these questions are so interesting.
00:02
I have a cat.
00:09
A drowsy cat, though.
00:12
A flower pot that sails up and then down past a window.
00:17
Okay.
00:20
It's in view for a total of five -tenths of a second.
00:31
And the height of the window is two meters.
00:43
How high above the window does the flower pot go? well, i don't know what this has to do with a drowsy cat.
00:51
But, oh, well, and i don't know why a flower pot is going up and down either.
00:57
Okay, so it's going up and down.
01:03
So, and we just know i'm going to write this dt.
01:10
I'm going to write this as dt and i'm going to leave this as h.
01:16
Okay.
01:18
Um, um, um, um, um.
01:31
So i did a problem.
01:32
Like this before and it took a long time.
01:36
So i'm trying to think about a better way.
01:40
So maybe we'll try to do this a different way.
01:46
We know that y equals y initial plus v initial t minus minus 1ā2g t squared.
02:04
Y minus y initial from the bottom to the top would be h.
02:12
V at the bottom of the window times dt minus one half g dt squared.
02:26
So we actually can figure out v at the bottom of the window because v, dt is going to equal h plus one -half g d -t squared.
02:53
Okay? and what am i trying to figure out? v -b.
03:00
V -b is going to be h plus one -half g -d -t squared over d -t.
03:15
Okay, well, let's figure out what v subb is.
03:19
So v subb, and i'm putting this in a desmos calculator, is h.
03:36
H is 2, dt is 0 .5, okay.
03:46
Oh, i can't actually write dt.
03:48
Eh, okay.
03:52
V sub b equals.
03:54
H plus one -half g, dt squared over dt.
04:11
Okay, i see my problem.
04:13
In my calculator, i had an issue.
04:21
Vb equals.
04:25
Okay, so that's going to be 6 .45 at the bottom of the window.
04:35
Okay.
04:37
How high does the flower pot go? how high above the window top does the flower pot go? well, y is going to equal y initial, which would be the bottom of the window...