Question
A particle moving at constant acceleration has velocities of $2.0 \mathrm{m} / \mathrm{s}$ at $t=2.0 \mathrm{s}$ and $-7.6 \mathrm{m} / \mathrm{s}$ at $t=5.2 \mathrm{s} .$ What is the acceleration of the particle?
Step 1
We can do this by subtracting the initial time from the final time. In this case, the initial time is $2.0s$ and the final time is $5.2s$. So, the time period is $5.2s - 2.0s = 3.2s$. Show more…
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