00:01
In this exercise, we have a more general transmission probability, t that's given here on the first line, by 1 plus u0 times the hyperbolic sign of kl squared, divided by 4eu0 minus e to the minus 1, where u0 is the height of the potential barrier, e is the energy of the particle, l is the length of the potential barrier, and k is equal to the square root of 2m times e.
00:31
U0 minus e divided by h bar.
00:35
In question a, we have to show that when kl is much greater than 1, the transmission probability reduces to the formula that we had before in the book.
00:50
That's the second equation here on the screen.
00:54
T is equal to 16e divided by u0 times 1 minus e divided by u0 times e to minus 2, kl.
01:01
So basically i'm going to take the first equation, and then i'm going to impose that kl is much greater than one.
01:11
First, notice that the hyperbolic sign of kl is equal to one -half of e to the kl minus -kl minus -k -l, and when kl is much greater than 1, e to the minus kl tends to 0, so this is approximately one -half of e to the k -kl.
01:32
So you can go back to the transmission, which is 1 plus u0 times the sign, the hyperbolic sign of kl, which as i just showed, is approximately e to the kl divided by 2 squared divided by 16eu0 minus e.
02:10
So this is, i'm sorry, it's not 16, this should be 4.
02:17
So this is equal to 1 plus u0 squared, e to the 2kl divided by 16, e u0 minus e to the minus 1.
02:34
Now notice that if kl is much greater than 1, then we have that the exponential of 2kl is much greater than 1, 1.
02:47
So we can disregard the first term that is this one here.
02:52
I'm simply going to disregard it.
02:55
So t is equal to is approximately equal to u0 squared e to 2kl divided by 16e u0 minus e to the minus 1.
03:14
And this is e to the minus 2kl times 16 e u0 minus e divided by u0 squared so this is equal to 16 e divided by u0 times 1 minus e divided by u 0 times e to the minus 2 kl okay so this is exactly the expression that we had the book for kl much wider than one.
03:54
Then we have to explain why imposing that kl is much greater than one implies that either the barrier is relatively wide or that the energy e of the particle is small compared with u0.
04:17
Well, notice that for k1, l to be much greater than one, either l is much greater than 1 over k, okay...