00:01
All right, this question is very easy if we just use the good old efficiency formula.
00:05
We know the exhaust, the energy leaping through the exhaust is going to be qc, and that's going to be 8 .0 times sensitive 3 joules.
00:12
We know the efficiency of the heat engine is 0 .25.
00:15
And so if we use this formula, and we recognize that work is the change in energy, so that's going to be qh minus qc.
00:22
And then, of course, for efficiency, we're dividing by qh.
00:25
Then if we, since we know qc and we know e, if we just rearrange this to solve for um solve for q h we'd get the q h uh is going to be equal to uh qc divided by one minus e and if we plug the numbers in we'd get 8 .00 times 10 to the three jewels divided by 1 minus 0 .25 giving us an answer of about 10 .7 times 10 to the 3 joules right so that's the answer for part a now we have to work with the power.
01:03
We know the power is just equal to work over time...