We are given the total volume of the water (50 L) and the specific volume at 40°C (0.1008 m³/kg). Converting the total volume to cubic meters gives us 0.05 m³. So, the mass (m) is given by:
\[m = \frac{V}{v} = \frac{0.05 \, m^3}{0.1008 \, m^3/kg} = 49.61 \, kg\]
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