00:01
In this question, we have a non -uniform charge rod.
00:05
So, it's length l, and then it has a charge density.
00:12
Lambda equals to alpha x.
00:14
Okay, and in this question, there are two parts.
00:17
In part a, you want to find a units of alpha.
00:19
In part b, you want to find the electric potential at point a.
00:24
So to do part a for the units of alpha, first we start with the equation, equals to alpha x and recognize that lambda is the linear charge density so the units of lambda will be coulum per meter and then the units of x would be meter and for units of alpha will then be units of lambda divide by units of x this is equal to cologne per meter square so this is the answer for part a next, in part b, you want to find the electric potential at point a.
01:06
So this is a continuous charge distribution, so we are not able to do it like point charge.
01:14
So what we'll do is to consider a small piece of charge bq here, and call it lambda the x, and then we are going to find the electric potential due to this small charge, and call it dv at point a.
01:30
And so this is ke, dq over r, okay? and then the ke is one over for pi epsilon not...