00:01
In this question, we have a straight cylindrical wire along the x -axis.
00:07
And then it has a length of 0 .5 meters.
00:15
The diameter is 0 .1 m m.
00:18
And then the resistivity is 4 times the diameter is 0 .2 m.
00:27
Sorry.
00:30
And then the resistivity is 4 times 10 to the power of negative 8 omel meters.
00:34
And then, so this is measured from x equals to the zero, from x equals to l, okay, where l is 0 .5 meters.
00:50
And then here the voltage is 4 volts, and the voltage here is 0 volts.
01:00
Okay, so we want to find the electric field in the wire, resistance, electric current in the wire, current density, and show that e equals to resistivity times the current density.
01:15
So, and then if, and we also need to express vectors in vector notation.
01:22
So in part a, you want to calculate the electric field.
01:26
So using e equals to negative delta v over delta x, x, x, okay? and we have e to be negative, so 0 minus 4 divide by 0 .5 minus 0 xxx and you calculate this to be 8 .0 volt per meter x hat.
01:57
Okay, so this is the answer for part a.
02:03
In part b you want to calculate resistance.
02:07
You'll be using r equals to row l over a.
02:15
Okay.
02:16
And the reservoir the resistance is row l over pi r square...