00:08
This question asks us for the iupac name for alpha farnassine, which is drawn below.
00:14
So first off, i want to start by numbering it, and we're going to do this to make every double bond as low as it can be.
00:21
So we'll start over here.
00:22
So one, two, three, four, five, six, seven, eight, nine, ten, eleven, twelve.
00:31
So we have 12.
00:32
So that's doeca.
00:35
We have three methyl groups on here at 3, 7, and 11.
00:42
So that will be the first part of the name.
00:45
3, 7, 11, trie methyl.
00:50
And then we also have our four double bonds on here.
00:54
They are at carbons 1, 3, 6, and 10.
00:58
And then again, dodeca, 412.
01:03
And then we have four alkenes here.
01:06
So four is tetra.
01:09
And then e for the alkenes.
01:11
And then we're almost done, but not quite.
01:13
We still have to account for stereochemistry...