We can do this by using the density of butane and the molar mass of butane. The density of butane is given as 0.573 g/mL and the molar mass of butane is 58.12 g/mol. So, we have:
\[11.5 \, \text{mL} \times \frac{0.573 \, \text{g}}{1 \, \text{mL}} \times \frac{1
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