00:01
In this question, we have an antenna.
00:03
Okay, the antenna looks like this.
00:06
So, okay, it's a square loop, okay, with entrance, okay, entrance, and then this is 10 cm, and, okay, this is also 10 cm.
00:33
Okay, and then this is connected with a resistor, and then with a capacitor.
00:40
And then there's a current that is flowing in the circuit.
00:50
It has an l, the self -inductance.
00:55
There's something that we need later.
00:58
Okay, so in this part is about how an antenna collect information or energy from electromagnetic wave and then from the energy that it collects from the energy that it collects from the energy.
01:13
The antenna it drives the circuit and then we want to find out the magnetic flux induce the mf the capacitance for resonant frequency and the rms value for the current and slowing in the circuit okay so to do this question okay in part a we want to find a magnetic flux okay we are given the the em wave.
01:47
Okay, it looks like this.
01:50
The electric view is emax, cosine, kz minus omega -t, j hats, and then we are given that the coordinate system.
02:08
It looks like this.
02:10
This is x, this is y this is z okay based on the given expression the wave is propagating along the plus z head direction and with e in the j with e in j hat okay then we need our b then b is in negative i hat so that e cross b gives z heads okay so which is the propagation of propagation of the em wave okay so our magnetic field vector is b equals to b max cosine k z minus omega t in the negative i head direction okay and then we know that c b max is equal to e max okay there's something with that we need later okay so in part a you want to find a magnetic flux so the definition of magnetic flux is b.
03:41
D a okay so the d a i'm going to make my d a to be in the negative i head direction.
03:59
Okay, so the a is going to be from the diagram.
04:07
Okay, so the b field is pointing in this direction.
04:14
Okay, and then i'm going to set my da in this direction.
04:17
And then my da will be expressed in terms of d .a.
04:23
D z okay it will be a times d z okay so a times d z um negative i had okay so by doing so then my uh magnetic flux is going to be positive okay so uh b max um cosy k z minus omega t times a d z okay okay integrate from minus a over 2 to a over 2 okay the origin of the coordinate system is at the center of the coin okay so take out the b max and a since they are the constants you integrate cosine you get sign and then because you are integrating over z respect to z so you get one over k x x minus omega t okay a over two integrating from negative a over two to a over two okay so b max a over k times si k a over two minus omega t minus si si x minus k a over two minus k a over two minus k a over two minus omega t okay so you simplify further okay so the second expression note that sine negative x is equal to negative sine x okay so we can pull out the negative sign and you get a plus and then after that you use a given identity okay so the given identity is um sign a plus b plus sine a minus b okay is equal to two sine a cosine cosine b okay so we can actually simplify this whole thing as two sine k a over two uh cosine omega t okay so this will be the 2b max a over k x x x k a over 2 cosy omega t so this is the magnetic flux okay so this is our answer for part a next in part b you want to calculate the induce mf so to calculate the induce mf using for this law okay we say that d induced is equal to negative defy b t yes there's one thing i forgot to add there's a n okay in each step okay so what i calculated is the many flux for one coin so if you need and coins that means be two times n k okay so the einduce is negative dd t of the magnetic flux which is 2n b max a over k, si k a over 2, cosine, cosine omega t.
08:42
Okay and you differentiate there's only the one thing that is as a function of time.
08:49
So differentiate cosine you get negative sine so and then you also get that omega out okay and you see that omega of k is c okay to n c b max uh times a okay times x k x k a over 2 sine k omega t okay so this is the the emf generated okay, next in part c you want to find the capacitance for resonance to take place.
09:43
Okay, so we are given the frequency is 4 megahertz...