An incompressible fluid with density $\rho$ is in a horizontal test tube of inner cross-sectional area $A$ . The test tube spins in a horizontal circle in an ultracentrifuge at an angular speed $\omega$ . Gravitational forces are negligible. Consider a volume element of the fluid of area A and thickness $d r^{\prime}$ adistance $r^{\prime}$ from the rotation axis. The pressure on its inner surface is $p$ and on its outer surface is $p+d p .(\text { a) Apply }$ Newton's second law to the volume element to show that $d p=\rho \omega^{2} r^{\prime} d r^{\prime} .$ (b) If the surface of the fluid is at a radius $r_{0}$ where the pressure is $p_{0}$ , show that the pressure $p$ at a distance $r \geq r_{0}$ is $p=p_{0}+\rho \omega^{2}\left(r^{2}-r_{0}^{2}\right) / 2 .(\mathrm{c})$ An object of volume $V$ and density $\rho_{o b}$ has its center of mass at a distance $R_{\text { cmob }}$ from the axis. Show that the net horizontal force on the object is $\rho V \omega^{2} R_{\mathrm{cm}},$ where $R_{\mathrm{cm}}$ is the distance from the axis to the center of mass of the displaced fluid. (d) Explain why the object will move inward if $\rho R_{\mathrm{cm}}>\rho_{\mathrm{cb}} R_{\mathrm{cmod}}$ and outward if $\rho R_{\mathrm{cm}}<\rho_{\mathrm{ob}} R_{\mathrm{cmob}}(\mathrm{e})$ For small objects of uniform density, $R_{\mathrm{cm}}=R_{\mathrm{cmob}}$ What happens to a mixture of small objects of this kind with different densities in an ultracentrifuge?