00:01
So for a problem like this, it's a good idea to just keep all of our units labeled very clearly.
00:07
So the mass of what we're working with is going to be 5 .95 kilograms.
00:16
And then i'm going to keep all of my x directions and y directions separate.
00:20
It's like one of the benefits of working with a vector.
00:23
So my x direction, my initial, the actual acceleration, so the net acceleration is going to be one.
00:35
1 .17 meters per second squared.
00:40
So we can, accelerations meters per second squared.
00:45
And then we have three forces acting on it.
00:49
So the total force in the x direction.
00:53
So let's find our net force will be our mass times acceleration.
01:00
So our net force is just going to be 1 .17 times 5 .95 in the x direction.
01:12
Okay.
01:12
So one.
01:13
1 .17 times 5 .95.
01:16
It's going to be 6 .9615.
01:19
Let's just go ahead and keep it.
01:24
Okay.
01:24
And that's going to be our net force in the x direction.
01:28
Okay.
01:29
It wants us to find our third force.
01:31
And it gives us the first force.
01:34
So f1 in the x direction is going to be 3 .22.
01:43
And f2 in the x direction is negative 1 .5...