Block B in Fig. 6-52 weighs 711 N. The coefficient of static friction between block and table i

Block B in Fig. 6-52 weighs 711 N. The coefficient of...

Key Concepts

Static Equilibrium

Static equilibrium refers to a state where a system is at rest, and the sum of all forces and moments acting on it equals zero. This concept is fundamental in analyzing structures or bodies that remain stationary with all net forces balancing one another, ensuring that there is no linear or rotational acceleration.

Static Friction

Static friction is the force that resists the initial movement between two surfaces in contact. It acts up to a maximum value, which is the product of the coefficient of static friction and the normal force. Understanding static friction is crucial in problems involving objects on surfaces where motion is about to occur but is prevented by a resisting frictional force.

Free-Body Diagrams

A free-body diagram is a schematic representation that depicts all external forces acting on an individual body. This tool is essential for visualizing and analyzing the forces in play, facilitating the application of Newton's laws to determine unknown quantities such as the tension in a rope or the force of friction.

Tension Forces

Tension forces appear in situations where a rope, cable, or string is used to connect bodies. They transmit force from one object to another and are analyzed by considering the equilibrium of forces acting along the direction of the rope. Understanding tension is important when solving problems involving connected objects to ensure the system remains static.

Transcript

00:01 First of all we're going to draw the diagram which is given in the position that is block a and block b which is connected by the rope.

00:06 So basically see this is block this is some you know stationary things over here and this is block b and it is connected by the rope till horizontal yet over here and it is now at this point at this junction this is point connected to a one more block a and now and there is a wall over here over here and the the string now the rope is hanging to this one with the angle which is given that is equal to 30 degree that so we need to find the maximum weight of this block a so that the the block system is in a stationary so that the system will be a stress nutty okay and the friction force within block b and this one is given 0 .25 and the weight of the block b that is also given that is 711 newton.

00:59 We need to find just the block a, okay? block a acceleration.

01:02 See if we see the tension, this is horizontal we have given.

01:06 So if this tension is t1 in this stream and let's say tension is t1 in this string and let's say tension t2 is in this string, okay? so if block is in a stationary, that means the frictional force, that means fx max, we need to find the maximum value of here.

01:25 So f max fixional force for b that should be equal to t1 okay and now t2 cost theta will be t1 for balancing this point okay so t1 is also equal to t2 cost of theta and now t2 sine theta will be mg t2.

01:44 T2s sorry t2 sine theta that is vertical so with m g so m a into g right first of all we need to find the t2 so we will obviously find the mass a so how we can find so, frictional force equals to t t1.

01:59 So t1 will be nothing but fr max, fr max will be what? and then total normal force into that 0 .25.

02:07 That means 1 by 4, obviously.

02:09 So 711 upon 4 newton.

02:11 So this will be the t1.

02:13 So t2 will be what? so t2 will be just the t1 upon cost theta...

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