Question
Calculate $\Delta S_{\text {surr }}$ for the following reactions at $25^{\circ} \mathrm{C}$ and 1 atm.a. $\mathrm{C}_{3} \mathrm{H}_{5}(g)+5 \mathrm{O}_{2}(g) \longrightarrow 3 \mathrm{CO}_{2}(g)+4 \mathrm{H}_{2} \mathrm{O}(t) \Delta H^{\circ}=-2221 \mathrm{~kJ}$b. $2 \mathrm{NO}_{2}(g) \longrightarrow 2 \mathrm{NO}(g)+\mathrm{O}_{2}(g)$$\Delta H^{\circ}=112 \mathrm{~kJ}$
Step 1
For both reactions, we are given the values of $\Delta H$ and the temperature is given as $25^{\circ} \mathrm{C}$. We need to convert this temperature to Kelvin by adding 273.15: $T = 25 + 273.15 = 298.15 \, \mathrm{K}$ Show more…
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Calculate $\Delta S_{\text { surr }}$ for the following reactions at $25^{\circ} \mathrm{C}$ and 1 $\mathrm{atm}$ . a. $\mathrm{C}_{3} \mathrm{H}_{8}(g)+5 \mathrm{O}_{2}(g) \longrightarrow 3 \mathrm{CO}_{2}(g)+4 \mathrm{H}_{2} \mathrm{O}(l)\Delta H^{\circ}=-2221 \mathrm{kJ}$ b. $2 \mathrm{NO}_{2}(g) \longrightarrow 2 \mathrm{NO}(g)+\mathrm{O}_{2}(g) \qquad \Delta H^{\rho}=112 \mathrm{kJ}$
Calculate $\Delta S_{\text {sur }}$ for the following reactions at $25^{\circ} \mathrm{C}$ and 1 atm. $$\text { a. } \mathrm{C}_{3} \mathrm{H}_{8}(g)+5 \mathrm{O}_{2}(g) \longrightarrow 3 \mathrm{CO}_{2}(g)+4 \mathrm{H}_{2} \mathrm{O}(l)$$$$\begin{aligned} &\Delta H^{\circ}=-2221 \mathrm{kJ}\\ &\text { b. } 2 \mathrm{NO}_{2}(g) \longrightarrow 2 \mathrm{NO}(g)+\mathrm{O}_{2}(g) \quad \Delta H^{\circ}=112 \mathrm{kJ} \end{aligned}$$
Calculate $\Delta S_{\text {surf }}$ for the following reactions at $25^{\circ} \mathrm{C}$ and 1 atm. a. $\mathrm{C}_{3} \mathrm{H}_{3}(g)+5 \mathrm{O}_{2}(g) \longrightarrow 3 \mathrm{CO}_{2}(g)+4 \mathrm{H}_{2} \mathrm{O}(l) \Delta H^{\circ}=-2221 \mathrm{~kJ}$ b. $2 \mathrm{NO}_{2}(g) \longrightarrow 2 \mathrm{NO}(g)+\mathrm{O}_{2}(g) \quad \Delta H^{\circ}=112 \mathrm{~kJ}$
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