Calculating Area with Green's Theorem If a simple closed curve C in the plane and the region $R$ it encloses satisfy the hypotheses of Green's Theorem, the area of $R$ is given by
Green's Theorem Area Formula
Area of $R=\frac{1}{2} \oint_{c} x d y-y d x$
The reason is that, by Equation (4) run backward,
Area of $R=\iint_{k} d y d x=\iint_{k}\left(\frac{1}{2}+\frac{1}{2}\right) d y d x$
$$=\oint_{c} \frac{1}{2} x d y-\frac{1}{2} y d x$$
Use the Green's Theorem area formula given above to find the areas of the regions enclosed by the curves in Exercises $31-34$
The astroid $\mathbf{r}(t)=\left(\cos ^{3} t\right) \mathbf{i}+\left(\sin ^{3} t\right) \mathbf{j}, \quad \mathbf{0} \leq t \leq 2 \pi$