Charge on the capacitor is given by $Q=I \alpha e^{-\frac{t}{\Delta V \varepsilon_{0} \beta}}$, where $\alpha$ and $\beta$ are constant, $t=$ time, $I=$ current, $\Delta V=$ Potential difference then, dimension of $\frac{\beta}{\alpha}$ is same as dimension of
(A) $\frac{1}{\sqrt{\mu_{0} \varepsilon_{0}}}$
(B) $\mu_{0} \varepsilon_{0}$
(C) $\frac{\mu_{0}}{\varepsilon_{0}}$
(D) $\frac{1}{\mu_{0} \varepsilon_{0}}$