Question
Consider a straight edge being illuminated by a parallel beam of light with $\lambda=6 \times 10^{-5} \mathrm{~cm}$. Calculate the positions of the first two maxima and minima on screen at $\mathrm{t}$ distance of $50 \mathrm{~cm}$ from the edge.
Step 1
Here, $\lambda = 6 \times 10^{-5} \mathrm{~cm}$ is the wavelength of light. So, we have \[V = -\frac{2}{6 \times 10^{-5}} = -25.82 \times Y\] where $Y$ is the distance from the edge. Show more…
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Consider a straight edge being illuminated by a parallel beam of light with $\lambda=6 \times 10^{-5} \mathrm{~cm} .$ Calculate the positions of the first two maxima and minima on a screen at a distance of $50 \mathrm{~cm}$ from the edge.
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Consider a set of two slits cach of width $b=5 \times 10^{-2} \mathrm{~cm}$ and separated by a distance $d=0.1 \mathrm{~cm}$, illuminated by a rnonochromatic light of wavelength $6.328 \times 10^{-5} \mathrm{~cm}$. If a coavex lens of focal length $10 \mathrm{~cm}$ is placed beyond the double slit arrangement, calculate the positions of the minima insido the first diffraction minimum.
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