Question
Consider a straight edge being illuminated by a parallel beam of light with $\lambda=6 \times 10^{-5} \mathrm{~cm} .$ Calculate the positions of the first two maxima and minima on a screen at a distance of $50 \mathrm{~cm}$ from the edge.
Step 1
Here, $\lambda$ is the wavelength of light, and $d$ is the distance from the edge to the screen. Substituting the given values, we get $V = -\frac{2}{6 \times 10^{-5}} \times 50 = -25.82y$. Show more…
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Consider a straight edge being illuminated by a parallel beam of light with $\lambda=6 \times 10^{-5} \mathrm{~cm}$. Calculate the positions of the first two maxima and minima on screen at $\mathrm{t}$ distance of $50 \mathrm{~cm}$ from the edge.
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