00:01
Okay, so we're going to titrate an amine with some hydrochloric acid.
00:06
So let's start by looking at how much hcl it takes.
00:10
So 0 .925 molar times its volume and liters.
00:21
So i added 0 .0554 moles of hcl.
00:28
Therefore, since it's a 1 -1 ratio, i must have reacted with 0 .0554 moles of our r.
00:37
And h.
00:39
Well, we were also told that this was 2 .5 grams of the rnh.
00:47
So the molar mass is simply grams over moles.
00:53
So we'll take our 2 .5 grams and divide by our moles 0554 moles.
01:05
And that will give us our molar mass of this, and it is 45 .1 grams mole.
01:17
In a second experiment, we used a different amount of hcl, so the same molarity.
01:25
Let's go ahead and multiply now by its volume, the 29 .95 milliliters, but we'll put that into liters.
01:35
So this time we added 0 .0277 moles of hcl, and we added this to the 2 .5 grams of our rnh.
01:51
Well, now that we know the molar mass, we can go ahead and change that to grams.
01:55
I'm sorry, that to moles.
01:57
We're using the molar mass.
01:58
So it's 45 .1.
02:03
So 0 .054 moles of our amine, r &h.
02:11
So i'm adding a strong acid to a weak base.
02:15
So let's write a reaction for what's going to happen there.
02:18
Okay? our strong acid is going to react with our mean, our weak base.
02:27
So we're going to inform rnh2 plus.
02:32
I'm going to do an icf table, right, in moles, just trying to keep track of our moles here...