Consider $n$ independent trials, each of which results in one of the outcomes $1, \ldots, k$ with respective probabilities $p_{1}, \ldots, p_{k}, \quad \sum_{i=1}^{k} p_{i}=1 .$ Show that if all the $p_{i}$ are small, then the probability that no trial outcome occurs more than once is approximately equal to $\exp (-n(n-1)$ $\left.\sum_{i} p_{i}^{2} / 2\right)$.