00:01
We have a cone here and inscribed in it is a cylinder.
00:08
The height of the cone is supposed to be h and a radius of r.
00:26
So for part a, we're trying to optimize it to that it has a, the cylinder inscribed in the cone is inscribed in the cone is going to be large.
00:38
We're trying to maximize it.
00:40
So, we use the cylinder is going to be the volume.
00:46
The cylinder is equal to pi times x squared because this represents the radius, the radius of the cylinder.
01:00
And then we have h minus y, which represents the difference between the difference between the, the smaller, cone produced below and in the larger cone.
01:21
And using this expression, y equalling y divided by h, equalling x divided by r, we can generate the function y equalling x divided by h divided by r, which is a proportionality because this represents x, this represents y.
01:46
This is the height of h.
01:48
And the other one here, this is r, which is the radius...