Question
Find an equation of the tangent line to the graph of the given function at the indicated value of $x$.$$y=-x+\frac{8}{x} ; \quad x=2$$
Step 1
Using the power rule, the derivative of $-x$ is $-1$ and the derivative of $\frac{8}{x}$ is $-8x^{-2}$. So, the derivative of the function is $y'=-1-8x^{-2}$. Show more…
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