00:01
So we want to find the maximum, the absolute maximum, and the absolute minimum of the function f of x is equal to e to x minus 2x on 0 ,1.
00:14
So let's go ahead and first take the derivative of this, because we need to take the derivative to find critical points.
00:24
So f prime of x is going to be, well, the derivative of e to the x is just e to the x.
00:32
And the derivative of 2x would be just 2.
00:38
So now we could go ahead set this equal to 0, add the 2 over, and we get e to the x is equal to 2, take the natural log of each side, and we get x is equal to the natural log of 2.
00:51
So in this case we only end up with one critical point, and natural log of 2 is less than 1 and bigger than 0.
01:00
So we'll at least have this number here.
01:05
And so one thing we can also check is to see if this will be absolute max or min by using the second derivative and taking the second derivative of that function, well, e to the x will still just be e to the x, and then negative 2 is 0.
01:25
So let's go ahead and plug in natural log of 2 into the second derivative.
01:32
And so we get e natural log of 2, which is just 2...