Question
From Fig. $1.24$, the correct relation is(A) $\vec{A}+\vec{B}+\vec{E}=\overrightarrow{0}$(B) $\vec{C}-\vec{D}=-\vec{A}$(C) $\vec{B}+\vec{E}-\vec{C}=-\vec{D}$(D) All of the above
Step 1
Therefore, the sum of these vectors is zero. This can be written as: \[\vec{A}+\vec{B}+\vec{E}=\overrightarrow{0}\] Show more…
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