Question
From Fig. $2.51$, the correct relation isFig. $2.51$a. $\vec{A}+\vec{B}+\vec{E}=\overrightarrow{0}$b. $\vec{C}-\vec{D}=-\vec{A}$c. $\vec{B}+\vec{E}-\vec{C}=-\vec{D}$d. All of the above
Step 1
Therefore, according to the triangle law of vectors, the sum of these vectors would be equal to zero. Hence, we can write this as: \[\vec{A}+\vec{B}+\vec{E}=\overrightarrow{0}\] Show more…
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From Fig. $1.24$, the correct relation is (A) $\vec{A}+\vec{B}+\vec{E}=\overrightarrow{0}$ (B) $\vec{C}-\vec{D}=-\vec{A}$ (C) $\vec{B}+\vec{E}-\vec{C}=-\vec{D}$ (D) All of the above
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Question 12 Referring to the figure below, the correct relation is: A. →A + →B = →C B. →C + →B = →A C. →C + →A = →B D. →A + →B + →C = 0 No Answer
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