Give the name, empirical formula, and molar mass of the compound depicted in Figure P 3.39.

Name: Problem 39, Chapter 3: CHEMISTRY: The Molecular Nature of Matter and Change
Uploaded: 2021-05-08T19:44:19-08:00
Duration: 4 min 26 s
Channel: Shaelyn Deal
Description: Give the name, empirical formula, and molar mass of the compound depicted in Figure P 3.39.

Give the name, empirical formula, and molar mass of the...

Key Concepts

Empirical Formula

An empirical formula gives the simplest whole-number ratio of atoms of each element present in a compound. It is a simplified representation that conveys the proportion of each element without necessarily showing the exact number of atoms in a molecule.

Molar Mass

Molar mass is the mass of one mole of a substance, typically expressed in grams per mole. It is calculated by summing the atomic masses of all atoms in the compound's formula and is used to relate the mass of a substance to the number of moles present.

Chemical Nomenclature

This concept involves the systematic naming of chemical compounds according to guidelines (such as IUPAC rules). It requires identifying the functional groups, bonding arrangements, and structure of the compound so that a unique name is assigned that provides insight into its composition and structure.

Transcript

00:01 In this problem, we're going to be figuring out the name, empirical formula, and molar mass of this very roughly drawn compound.

00:13 We're given that the blue circles represent oxygen, the red ones represent phosphorus.

00:19 So the first thing we're going to do is figure out how many of those we have.

00:23 We have six oxygens and four phosphorus, which i'm going to put on top because phosphorus, comes first, it's here, and oxygen is to the right of that.

00:46 All right, next thing we need to do is determine whether or not, whether this is ionic or molecular.

00:53 Ionic compounds will have a metal involved, which are over here on the left side of the periodic table, whereas molecular formulas will have non -metals involved.

01:05 So we can see that both phosphorus and oxygen are non -metals.

01:09 So this is going to be a molecular compound.

01:15 Next thing we need to do is recall our prefixes, since we have multiple atoms of the same element present in this compound.

01:23 So we have four for phosphorus and six for oxygen.

01:28 The prefix for four is tetra.

01:34 The prefix for six is hexa.

01:38 And we need to recall, since that oxygen is our last element, it's also going to have eyed at the end.

01:47 So if we put all that together knowing that phosphorus comes first and has a prefix tetra, oxygen comes last, has the prefix hexa and the suffix i'd, the name of this compound is going to be tetraphosphorus hexa oxide.

02:15 That's its name.

02:18 The next thing we're going to do is determine our empirical formula.

02:22 We know our molecular formula, since we can count all of our atoms here and get p4.

02:30 06, that's our molecular formula, but our empirical formula is the simplest whole number ratio that we can get out of that...

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