00:01
If we're given that s of t is equal to t -q plus t, and the first part of the directions are to, for part a, find v of t.
00:12
Well, you should know for part a that s prime of t, the derivative of s will give you the velocity equation.
00:21
So that is your rule where you bring the 3 in front, t -squared plus 1.
00:26
That's your first answer to part a.
00:28
So where does this come into play? this lesson is all about the second derivative is for part b.
00:35
Because the second derivative means that's the derivative of velocity, which gives you acceleration.
00:43
So that's the derivative of what we just found, which would be 16.
00:46
The derivative of that constant would be zero, so that's no longer there.
00:50
So that's your answer to part b.
00:52
Part c is asking for when t equals 4...