00:01
All the gases in this reaction equation has the same temperature and pressure.
00:07
We can therefore say that any of the volume ratios will be equal to the corresponding mole ratios.
00:16
Now, in order to make use of this, we need to make sure that the reaction equation is balanced.
00:23
And in this case, it's not balanced yet.
00:27
We have three oxygens on the right.
00:31
4 on the left.
00:33
So let's balance this by adding it to in front of the s .o .3, sulfur trioxide.
00:44
And then we need to add two in front of the sulfur dioxide as well.
00:49
Right.
00:50
So this is the balanced equation.
00:52
And now, because both reactants volumes are given, one of them can be a limiting reactant.
01:02
So we need to identify which one of these is the limiting reactant.
01:10
And in order to do so, we will calculate the volume of the sulfur trioxide that forms when starting off with 3 litres of sulfur dioxide.
01:22
And then, yeah, we compare that with the volume of eso3 that forms when starting off with 1 .25 liters of oxygen gas.
01:32
So let's do the first calculation...