00:01
In this question, we can assume that all the gases have the same temperature and pressure.
00:06
We can therefore say that any volume ratio will be equal to the corresponding mole ratio.
00:13
Furthermore, we have to make use of the same reaction than in the previous question.
00:21
So i've copied the balanced one onto this page.
00:26
We can therefore start off by figuring out which one of the reactants is the limiting reactant because they give the volumes of both the reactants and any one of them can therefore limit the volume of eso3 that can form here.
00:42
For this purpose, we will calculate the volume of product that forms when starting off with so2, 1 .25 liters of eso2 and compare that to the volume of eso3 that forms when starting off with 3 litres of oxygen gas.
01:00
All right, so let's do the first calculation.
01:04
So the volume of so3 over the volume of so2 will be equal to the mole ratio of 2 over 2.
01:16
So this is 2 over 2, which is equal to 1.
01:21
Therefore the volume of so3 is equal to 1 times the volume of eso2.
01:26
So it's going to be the same volume.
01:28
So this is 1 times 1 .25.
01:33
Liters, which is just 1 .25 liters.
01:37
Right, now let's do the same type of calculation for oxygen...