00:01
In this question, we need to make use of the same reaction equation as in the previous question where we had to realize that the reaction equation was not balanced.
00:12
So the first thing that we did was we balanced the reaction equation.
00:15
And i've just copied that reaction equation here.
00:19
So it's already balanced.
00:21
Now, we need to determine the volume of the sulfur dioxide when reacting this with 25 .0 .0 .000.
00:30
Liters of oxygen gas.
00:33
Because we are working with a situation where both the temperature and the pressure are the same for all the gases, we can put a specific mole ratio equal to a corresponding volume ratio.
00:49
So let's take the number of moles of sulfur dioxide over the number of moles of oxygen here and this will be equal to 2 over 1.
01:08
Right, so 2 over 1 and this will be equal to the corresponding volume ratio.
01:13
So it's the volume of so2 over the volume of oxygen gas...