00:01
Okay, let's start by calculating the moles of barium hydroxide.
00:05
So i'm going to take its molarity and multiply by the liters of solution.
00:12
And we'll see that we're reacting 0 .0699 moles of the barium hydroxide.
00:23
Okay, let's do the same thing for the hcl.
00:27
Okay, 0 .12 molar times its volume, 0 .45 liters.
00:33
So we've got 0 .054 .0 moles of hcl.
00:42
Now let's write our balanced equation.
00:45
So i've got barium hydroxide.
00:50
It's going to react with two hcls to make barium chloride and two waters.
01:03
So it looks like we've got a limiting reactant problem here.
01:07
I'm going to start with 0 .069.
01:12
Moles and 0 .054 moles.
01:18
Well, it's a 2 to 1 ratio, so i need more hcl and actually have less, so that's obviously going to be my limiting reactant.
01:26
So minus 0 .0540...