00:01
So for this problem, we have two points of application, which are the force of screw and the force on the mechanism.
00:08
And we're going to use the coordinates for this, y .a and y, d.
00:18
So for our first one, our equation for force of screw will be two.
00:24
In parentheses, we have three times the sign of the angle.
00:30
And for yd we have 6 times 3 times the sign of the angle.
00:37
So we can rewrite these out to be.
00:43
For our ya we have delta, ya is equal to 6 times cosine of the angle and then delta angle.
00:58
So for yd we rewrite delta yd is equal to 18.
01:07
Times cosine with angle...