Question
If a radiation source has an intensity of $6.50 \mathrm{~Sv}$ at $1.0 \mathrm{~m},$ what distance is needed to decrease the intensity of exposure to below $0.25 \mathrm{~Sv}$, the level at which no effects are detectable?
Step 1
This relationship can be expressed as follows: \[I_1 / I_2 = (d_2 / d_1)^2\] where \(I_1\) and \(I_2\) are the intensities at distances \(d_1\) and \(d_2\) respectively. Show more…
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