Question
If $a_{n}=\sum_{r=0}^{n} \frac{1}{n_{r}_{r}}$, then $\sum_{r=0}^{n} \frac{r}{n_{r}}$ equals(a) $(n-1) a_{n}$(b) $n a_{n}$(c) $\frac{1}{2} n a_{n}$(d) None of the above
Step 1
Step 1: First, let's rewrite the given expression $\sum_{r=0}^{n} \frac{r}{n_{r}}$ as $\sum_{r=0}^{n} \frac{r}{\binom{n}{r}}$ for clarity. Show more…
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