Question
If $\sum_{i=1}^{2 n} \sin ^{-1} x_{i}=n \pi$, then $\sum_{i=1}^{2 n} x_{i}$ is equal to(A) $n$(B) $2 n$(C) $\frac{n(n+1)}{2}$(D) none of these
Step 1
We know that the maximum value that $\sin ^{-1} x$ can take is $\pi/2$. This is because the range of $\sin ^{-1} x$ is $[-\pi/2, \pi/2]$. Show more…
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