Question
If the tangent at $(1,1)$ on $y^{2}=x(2-x)^{2}$ meets the curve again at $P$, then $P$ is(a) $(4,4)$(b) $(-1,2)$(c) $(9 / 4,3 / 8)$(d) $(3 / 4,7 / 4)$
Step 1
We get \[\frac{dy}{dx} = \frac{2(2-x)(2-3x)}{y}\] Show more…
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