Question
If the tangent at $P(1,1)$ on $y^{2}=x(2-x)^{2}$ meets the curve again at $Q$ then the point $Q$ is(a) $(-1,2)$(b) $\left(\frac{9}{4}, \frac{3}{8}\right)$(c) $(4,4)$(d) None
Step 1
This gives us the slope of the tangent at any point on the curve. Differentiating both sides with respect to $x$, we get \[2y\frac{dy}{dx} = (2-x)^{2} - 2x(2-x).\] Show more…
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