Question
(II) (a) What is the minimum cross-sectional area required of a vertical steel cable from which is suspended a 270-kg chandelier? Assume a safety factor of 7.0. (b) If the cable is 7.5 m long, how much does it elongate?
Step 1
We can rearrange this equation to solve for A: \[A = \frac{F \times SF}{TS}\] where F is the force, SF is the safety factor, and TS is the tensile strength. Show more…
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(II) $(a)$ What is the minimum cross-sectional area required of a vertical steel cable from which is suspended a 320 -kg chandelier? Assume a safety factor of 7.0$(b)$ If the cable is 7.5 $\mathrm{m}$ long, how much does it elongate?
A 350-kg chandelier is suspended from vertical steel cable. The cable is 5.9 m long. Assume a safety factor of 8.5. The elastic modulus for steel is 2.0 x 10^11 N/m^2 and tensile strength for steel is 5.0 x 10^8 N/m^2. Part A What is the minimum cross-sectional area required of the cable? Express your answer to two significant figures and include the appropriate units. A_min Part B How much does the cable elongate? Express your answer to two significant figures and include the appropriate units. ΔL
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