Question
In $11-22,$ solve each triangle, that is, find the measures of the remaining three parts of the triangle to the nearest integer or the nearest degree.In $\triangle A B C, a=22, b=18,$ and $\mathrm{m} \angle C=130$
Step 1
We can find the length of side $c$ using the Law of Cosines. The Law of Cosines states that $c^2 = a^2 + b^2 - 2ab\cos(C)$. Substituting the given values, we get $c^2 = 22^2 + 18^2 - 2*22*18*\cos(130)$. Solving this, we get $c^2 = 1316.5$, so $c = \sqrt{1316.5} Show more…
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