Question
In $11-22,$ solve each triangle, that is, find the measures of the remaining three parts of the triangle to the nearest integer or the nearest degree.In $\triangle A B C, a=15, b=18,$ and $\mathrm{m} \angle C=60$
Step 1
c^2 = a^2 + b^2 - 2ab cos C = 15^2 + 18^2 - 2(15)(18)cos60° = 225 + 324 - 540(0.5) = 549 - 270 = 279. So c = √279 ≈ 16.703 ≈ 17 (nearest integer). Show more…
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