Question
In Exercises $5-10$ , find an equation for the tangent to the curve at the given point. Then sketch the curve and tangent together.$$y=x^{3}, \quad(-2,-8)$$
Step 1
The derivative of $y$ with respect to $x$ is $y'=3x^{2}$. Show more…
Show all steps
Your feedback will help us improve your experience
Joseph Liao and 98 other Calculus 1 / AB educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
In Exercises $5-10$ , find an equation for the tangent to the curve at the given point. Then sketch the curve and tangent together. $$ y=\frac{1}{x^{3}}, \quad\left(-2,-\frac{1}{8}\right) $$
Differentiation
Tangents and the Derivative at a Point
In Exercises $5-10,$ find an equation for the tangent to the curve at the given point. Then sketch the curve and tangent together. \begin{equation} y=4-x^{2}, \quad(-1,3) \end{equation}
Derivatives
In Exercises $5-10$ , find an equation for the tangent to the curve at the given point. Then sketch the curve and tangent together. $$ y=\frac{1}{x^{2}}, \quad(-1,1) $$
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD