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In Exercises 55 - 64, solve the system graphically or algebraically. Explain your choice of method.$ \left\{\begin{array}{l}y - e^{-x} = 1\\y - \ln x = 3\end{array}\right. $
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This gives us: \[ y = e^{-x} + 1 \] \[ y = \ln x + 3 \] Show more…
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