00:01
Okay, so in this problem, they want us to use a formula that's just above the problem set.
00:07
Okay, so the problem set we're dealing with, we have points 08, 16, 24, and 3, 2.
00:20
Okay, so all these are points.
00:25
Okay, and it gives us a formula to use n, where n's the number of points times b, plus sigma x, which is the sum of the x values times a, equals sigma y, which is the sum of the y values.
00:39
And our second equation is our sum of the x values times b plus the sum of the x values squared times a, and that's equal to the sum of the product of the x and y values.
00:54
So to determine these things, let's just make the list of all of our coefficients that we do know.
00:59
So end, the number of points we have is four.
01:04
The sum of our x values is six.
01:09
Some of our y values is 20.
01:13
Okay, so the sum of our x values squared.
01:18
Okay, well, that's going to be 0 plus 1 plus 4.
01:25
1 plus 4 is 5.
01:26
5 and 9 is going to be 14.
01:30
And the sum of our, the product of our x and y values is going to be 0 plus 6, plus 8, plus 6, which is 20.
01:38
Again.
01:41
Okay, so i'm going to use these coefficients on the next slide and we will solve our system of equations.
01:47
Okay, so we're going to have 4b plus 6a equals 20.
01:56
We will also have 6b plus 14a equaling 20.
02:09
We're going to solve these equations by elimination.
02:12
So i'm going to multiply my top equation by 3 and my bottom equation by negative 2...