00:28
So we want to find basis for eigenspaces for given values of lambda, right? so just straight off the bat, let's calculate, let's take v to be x1, x2, x3.
00:53
And for any lambda, let's just calculate what this equality gives us the conditions for x1 to x3, okay? so our a is 01 and our last row is v is x1 x2 x3 and this is lambda x1 lambda x2 okay now the first equation is just 4 times x1 plus x3 equals lambda times x1 so this gives us that x3 is equal to lambda minus 4 times x1.
02:10
Okay.
02:18
Second equation is negative 2 times x1 plus x2 equals lambda times x2.
02:28
This gives us negative 2 times x1 is equal to lambda minus 1 times x2.
02:45
Okay.
02:46
And the third equation is negative 2 times x1 plus x3 equals lambda times x3.
02:59
This gives us negative 2 times x1 is equal to lambda minus 1 times x3.
03:22
So combining these two equations, combining the second and third equation, you can see that, okay, so let's plug in specific values of and see what we get.
03:40
So when lambda is equal to 1, first equation tells you that x3 is equal to negative 3 of x1 and minus 2 x1 is 0.
03:54
So that gives you x1 is 0.
03:59
And third equation also tells you that x1 is 0.
04:03
Okay...