00:01
In this exercise, we have a diffraction experiment performed two times.
00:04
In the first one, the diffraction is performed with an electron and then the second one with a photon.
00:12
But in both, the wavelength of the particle is the same.
00:16
So the wavelength of the electron used is the same as the wavelength of the photon used.
00:23
And we have the information that the frequency of the photon that was used is 10 to the 19th hertz.
00:30
And our goal is to calculate what is the potential difference delta v that accelerated the electron that was used.
00:41
So in order to calculate delta v, we're going to need some steps.
00:47
And in the first one, i'm going to calculate the wavelength of the electron by calculating the wavelength of the photon since they are equal.
00:58
So from there, we can calculate the momentum of the electron, and from the momentum, the kinetic energy, and finally, from the kinetic energy we can calculate delta v.
01:11
So let's do it.
01:13
So first, notice that the wavelength of the photon is equal to the speed of light c divided by its frequency...